# Line slope calculator 5x-y=25

**Straight line given by points A[5; 0] and B[6; 5]**

## Calculation:

**Slope-intercept form of line:**y = 5x-25

**Canonical form of the line equation:**5x-y-25 = 0

**Parametric form of the line equation:**

x = t+5

y = 5t ; t ∈ R

**Slope:**m = 5

**Slope angle of line: φ =**78°41'24″ = 1.3734 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = -25

**Distance line from the origin:**d

_{0}= 4.9029

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(1; 5)

**Normal vector: n =**(5; -1)

**Midpoint of the segment AB: M =**[5.5; 2.5]

**Perpendicular Bisector equation:**x+5y-18 = 0

**Vector OA = (5; 0) ; |OA| = 5**

**Vector OB = (6; 5) ; |OB| = 7.8102**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 39°48'20″ = 0.6947 rad**