# Line slope calculator 6x+4y=40

**Straight line given by points A[0; 10] and B[4; 4]**

## Calculation:

**Slope-intercept form of line:**y = -1.5x+10

**Canonical form of the line equation:**6x+4y-40 = 0

**Parametric form of the line equation:**

x = 4t

y = -6t+10 ; t ∈ R

**Slope:**m = -1.5

**Slope angle of line: φ =**-56°18'36″ = -0.9828 rad

**X intercept:**x

_{0}= 6.6667

**Y intercept:**y

_{0}= q = 10

**Distance line from the origin:**d

_{0}= 5.547

**The length of the segment AB: |AB| =**7.2111

**Vector: AB =**(4; -6)

**Normal vector: n =**(6; 4)

**Midpoint of the segment AB: M =**[2; 7]

**Perpendicular Bisector equation:**4x-6y+34 = 0

**Vector OA = (0; 10) ; |OA| = 10**

**Vector OB = (4; 4) ; |OB| = 5.6569**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 45° = 0.7854 rad**